A few days ago
Somebody

Can someone help?

The length of a rectangle is 4 cm more than 2 times its width. If the area of the rectangle is 61 cm2, find the dimensions of the rectangle to the nearest thousandth.

Top 2 Answers
A few days ago
♥becauseisme♥

Favorite Answer

I think…

L=4+2(w)

W=w

A=61cm2

A=L*W

4+2(w)*w=61

2(w)*w=57

2w^(quare)=57 57/2=28.5

w=Root two 28.5

w=5.3385

L=14,67707…

Hope this helps…

Im not sure though…

smart people please correct this 😛

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A few days ago
Joymash
Let the width be w

from the statement the length

(l) = ( 2*w+4) [Equation 1]

Area = length * width

= w(2w+4)= 61

= 2w^2+4w = 61

Or 2w^2+4w – 61 = 0

From the above quadratic equation

w = {- b +or-√ (b^2 – 4ac)}/2a [Equation 2]

Where a= 2, b = 4 and c = – 61

Using the above values in eqn 2

w = {- 4 + √ [4*4 – 4*2(-61)]}/2*2

or {- 4 – √ (4*4 – 4*2(-61))}/2*2

width cannot be –ve

hence {-4 + √ 504 } / 4

= {-4 + 22.45}/4

i.e. {-4+ 22.45}/4

hence w = 18.45/4 = 4.613

using the value of w in equation 1

l = 13.225

Area = length * width

= 13.225*4.613

=61.007

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