Can anyone explain this problum step by step to me? 1/4[3-2(y+1)]-1/3[2-(y-6)]?
Favorite Answer
P stands for parenthesis:
1/4[3-2y+2]-1/3[2-y-6] — Bassically, i distributed the 2 and got rid of the parenthesis. Now, you have to simplify.
1/4[5-2y] – 1/3[-y-4] There, now we distribute the 1/4 and 1/3 to simplify and get out the remaining parenthesis(or the brackets in our case)
[5/4-1/2y] – [-1/3y-4/3] — now to sum it all up: combine like terms, but first lets get some common denomenators:
[15/12-3/6y] – [-2/6y-16/12] — just made it simple by making the integers both have a denomenator of 12, and the variables to have a denominator of 6. Let’s finish now:
31/12 – 1/6y — Now that should be your answer, hope this helped!!
1/4[3-2y-2]-2/3[2-y+6]
1/4[-2y+1]-2/3[-y+8]
-2y/4+1/4+2y/3-16/3
um.. you can do the math form here./..
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