Calculus question?

Find dy/dx.

x+tan(xy)=0

Find dy/dx.

x+siny=xy

Top 1 Answers

A few days ago

Anonymous

Favorite Answer

x+tan(xy)=0

Differentiating with respect to x:

1 + [ sec^2(xy)(x dy/dx + y) ] = 0

x sec^2(xy) dy/dx = -1 – y sec^2(xy)

dy/dx = [ -1 – y sec^2(xy) ] / [ x sec^2(xy) ].

x+siny=xy

1 + cos(y)dy/dx = x dy/dx + y

(cos(y) – x)dy/dx = y – 1

dy/dx = (y – 1) / (cos(y) – x).

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