A few days ago
calculus ???
Could you guys help me with this ?
find an equation of the tangent line to the curve at the given point :
Y = 2X^3 – 5x
given point : (-1, 3)
Top 2 Answers
A few days ago
Favorite Answer
Differentiate the curve first.
y = 2x^3 – 5x
y’ = 6x^2 – 5
Plug in x = -1
y’ = 6(-1)^2 – 5
y’ = 6 – 5
y’ = 1
The slope of the tangent line is 1.
m = 1
Also,
x = -1
y = 3
Plug m, x, and y into the equation for a line y = mx + b and solve for the only unknown variable, b.
3 = 1 (-1) + b
3 = -1 + b
4 = b
So, the equation for the tangent line is:
y = x + 4
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A few days ago
It has been a while since I have done this, but I believe that you have to find the instantaneous slope at (-1,3) and then use that to find the answer. Thats all I can remember… and my calculus notebook is nowhere to be found.
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