A function is even if f(x) = f(-x). A function is odd if f(-x) = -f(x). It’s neither if neither works.

h(x) = x/(x^2 – 1)

h(-x) = -x/((-x)^2 – 1) = -x/(x^2 – 1)

so h(-x) = -h(x) and it’s odd

h(x) = -x^3/(3x^2 – 9)

h(-x) = -(-x)^3/(3(-x)^2 – 9)

= x^3/(3x^2 – 9)

So h(-x) = – h(x) and it’s odd

If I’ve misread the question – if those weren’t both denominators – then my answers will be wrong, but the procedure will still work. In the future, parentheses will make it a WHOLE lot easier to figure out what you’re asking.

1]

h(x) = x/(x^2-1)

=-x/(-x^2-1)

=-x/(x^2-1)

*From here, we can see that the numerator of X is negative, there is no way to change it, so the function is NEITHER.

EDIT : Put down Odd instead of neither :p

2] h(x) = -x^3 / (3x^2 – 9)

=-(-x^3)/(3(-x^2) – 9)

= x^3/ (3x^2-9)

*Since the numerator is now positive, the function is no longer like before in any way, thus, it is NEITHER.

2nd odd im pretty sure like 90% positive those are right