algebra 2 word problem question?

Q: Find all ests of three consecutive odd integers whose sum is between 20 and 30.

20<(X)+(x+2)+(x+4)<30 20<3x+6<30 14<3x<24 14/3

Top 3 Answers

A few days ago

hottotrot1_usa

Favorite Answer

Find all “ests”? What are “ests”? sets? okay.

Your analysis has shown that 14/3

A few days ago

gee

so, what’s the problem now?

u got the value of X between 4.667 and 8. you took the smallest possible odd from the given range and that is 5.

i.e. x = 5, x + 2 = 7, and x + 4 = 9

Now, the next odd in the possible range (4.667 < x < 8) is 7 so, x = 7, x + 2 = 9, and x + 4 = 11, that sums up to 27 {5, 7, 9} and {7, 9, 11} are the possible answers. Let me know if you meant something else.

A few days ago

pound it.

you can’t put the x’s together & 2 and 4 because they are in perentheses. so u would have to find the answers for (X)+(x+2)+(x+4)=21,22,23,24,25,26,27,28,&29 since theyre all in between 20 & 30. i got 5, 5 1/3, 5 2/3, 6, 6 1/3, 6 2/3, 7, etc…9. so you void all the others besides 5, 7, and 9 because those three are consecutive odd numbers (odd numbers one after another). sounds confusing but if you think about it it’ll make sense.

omg whats the correct answer…………….?

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algebra 2 word problem question?

algebra 2 word problem question?

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