algebra 2 need help?
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and for mocha blend coffee be y
Customer 1:
2x + 3y = 28 —eq1
Customer 2:
4x + 2y = 32 —eq 2
Multiplying eq 1 by -2 and then adding eq 2
-4x -6y = -56 — eq 1 x -2
4x + 2y = 32 — eq 2
After addition we get
-4y = -24
4y = 24
y = 24/4 = 6
Substituting the value of y in eq 1, we get
2x + 3 ( 6) = 28
2x + 18 = 28
2x = 28-18
2x = 10
x = 5
Therefore the cost per pound for Kona Blend coffee is 5 and Mocha blend coffee is 6
2k + 3m = $28
4k + 2m = $32
k= kona-blend
m=mocha-blend
Subtract the 2 equations.
4k + 2m = $32
– 2k + 3m = $28
————————–
2k – m = $4
Solve for m m = -1(4 – 2k)
m = -4 + 2k
Use this equation to substitute back into one of your original equations.
4k + 2(-4 + 2k) = 32
4k + -8 + 4k = 32
8k – 8 = 32
8k = 40
k = 40/8
k = 5
So we know the Kona-blend costs 5 dollars a lb.
So use this information to find out the cost of m mocha-blend
We said m = -4 + 2k, so put in our value for k!
m = -4 + 2(5)
m = -4 + 10
m = 6
Mocha-blend costs 6 dollars a lb.
Check: 2(5) + 3(6) = 28
10 + 18 = 28!
Hope this helps!
kona – x
mocha – y
2x +3y = 28
4x +2y = 32
now take the first equation and solve for x… x= (-3y)/2 + 28/2
take that x and plug it into the second equation
4((-3y)/2 +28/2) +2y = 32
now solve for y….i get y=6
and plug that in the first again… 2x + 3(6) =28
solve for x … i get x =5
i think
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