A few days ago
c0r@z0n

algebra 2 need help?

for $28, a customer purchased 2 pounds of a kona-blend coffee and 3 pounds of a mocha-blend coffee. a second customer purchased 4 pounds of the kona coffee and 2 pounds of the mocha coffee for a total of 32. find the cost per pound of each type of coffee.

Top 4 Answers
A few days ago
Varshita

Favorite Answer

Let the cost per pound for kona blend coffee be x

and for mocha blend coffee be y

Customer 1:

2x + 3y = 28 —eq1

Customer 2:

4x + 2y = 32 —eq 2

Multiplying eq 1 by -2 and then adding eq 2

-4x -6y = -56 — eq 1 x -2

4x + 2y = 32 — eq 2

After addition we get

-4y = -24

4y = 24

y = 24/4 = 6

Substituting the value of y in eq 1, we get

2x + 3 ( 6) = 28

2x + 18 = 28

2x = 28-18

2x = 10

x = 5

Therefore the cost per pound for Kona Blend coffee is 5 and Mocha blend coffee is 6

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A few days ago
Anonymous
First, you want to make 2 equations.

2k + 3m = $28

4k + 2m = $32

k= kona-blend

m=mocha-blend

Subtract the 2 equations.

4k + 2m = $32

– 2k + 3m = $28

————————–

2k – m = $4

Solve for m m = -1(4 – 2k)

m = -4 + 2k

Use this equation to substitute back into one of your original equations.

4k + 2(-4 + 2k) = 32

4k + -8 + 4k = 32

8k – 8 = 32

8k = 40

k = 40/8

k = 5

So we know the Kona-blend costs 5 dollars a lb.

So use this information to find out the cost of m mocha-blend

We said m = -4 + 2k, so put in our value for k!

m = -4 + 2(5)

m = -4 + 10

m = 6

Mocha-blend costs 6 dollars a lb.

Check: 2(5) + 3(6) = 28

10 + 18 = 28!

Hope this helps!

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A few days ago
noneofyurbusiness
i think you can use substitution…

kona – x

mocha – y

2x +3y = 28

4x +2y = 32

now take the first equation and solve for x… x= (-3y)/2 + 28/2

take that x and plug it into the second equation

4((-3y)/2 +28/2) +2y = 32

now solve for y….i get y=6

and plug that in the first again… 2x + 3(6) =28

solve for x … i get x =5

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A few days ago
~Zippy~Lil’ Mar~
find the %age of each kind of coffee for each buyer, then multiply that by the total price,

i think

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