A few days ago
kace

algebra 2 help…solution sets….please?

exclamation points stand for absolute value….

3x – 8 = 4

soultion set {integers}

4x – 7 = 3

solution set {integers}

(2x – 6)(3x + 2) =0

soultion set {rational numbers}

!3x + 7! = 25

solution set {positive numbers}

x^2 = 49

solution set {real numbers}

Top 2 Answers
A few days ago
Marcella S

Favorite Answer

3x-8=4 add 8 to both sides

3x=12

x=4

solution set: {4}

4x-7=3 add 7 to both sides

4x=10 divide both sides by 5

x=10/4 simplify

x=5/2

solution set: {5/2}

(2x-6)(3x-2)=0 set each factor equal to zero

2x-6= 0 or 3x-2=0 add pure number to both sides

2x=6 or 3x=2 divide both sides by coefficient of x

x=3 or x=2/3

solution set: {3, 2/3}

!3x-7!=25

3x-7=25 or 3x-7=-25 add pure number to both sides

3x=32 or 3x=-18 divide both sides by 3

x=32/3 or x=-6

solution set: {32/3, -6}

x^2=36 take square root of both sides

x=7 or x=-7

solution set: {-7, 7}

x

1

A few days ago
edith p
3x – 8 = 4

3x = 8 + 4

3x = 12

x = 4

4x – 7 = 3

4x = 7 + 3

4x = 10

x = 10/4 or 2 1/2

(2x – 6) (3x + 2) = 0

2x – 6 = 0

2x = 6

x = 3

3x + 2 = 0

3x = -2

x = -2/3

!3x + 7! = 25

(3x + 7) = 25 or -(3x + 7) = 25

3x + 7 = 25 or -3x – 7 = 25

3x = 25 – 7 -3x = 25 + 7

3x = 18 -3x = 32

x = 6 or x = -32/3 or -10 2/3

0