A few days ago
ALGEBRA 1 Homework HELP!!?
THE DIFFERENCE OF TWO NUMBERS IS 33. IF FOUR TIMES THE LESSER NUMBER IS SUBTRACTED FROM THREE TIMES THE GREATER NUMBER, THE DIFFERENCE IS 62. Find the numbers.
plz help. i’ll appreciate it. =(!
Top 4 Answers
A few days ago
Favorite Answer
Let L= the lesser number and G= the greater number.
G-L=33 and 3G-4L=62
G-L=33 converts to G=L+33
Using substitution you get 3(L+33)-4L=62
Solving for L…. 3L+99-4L=62
……………………. -L+99=62
……………………. -L=-37
……………………. L=37
Plug in value for L to find G.
G-37=33
Solve for G.
G=70
G=70 and L=37
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A few days ago
70 and 37
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A few days ago
Let the smaller number be X and the larger number by Y. So you have the equations:
Y – X = 33
3Y – 4X = 62
You can solve them simultaneously.
Y = 70
X = 37
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A few days ago
Ok. so number A-B=33
B is the lesser #
3A-4B=62
Add the two equations:
A-B=33
3A-4B=62
Multiply the A-B=33 by -3
you get -3A+3B=-99
add it to 3A-4B=62
you get -B=-37
B=37*
A-37=33
A=100*
*answer
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