A few days ago
sensitivelyambiguous

a very hard math question?

a right circular cone is divided into 2 portions, L and M, by a plane parallel to the base. The height of each portion is k units. Find the ratio of the volume of L to the volume of M.

Top 1 Answers
A few days ago
Anonymous

Favorite Answer

the volume of the cone is V = (1/3)πr^2h

where r = radius and h = height

since it is split in 2 parts with equal height k

the height of the big cone is h = 2k

so

V = (1/3)πr^2(2k) = (2/3)πr^2k is the volume of the big cone

now

the top portion is a cone with radius = r/2 and height = k

so

v = (1/3)π(r/2)^2k = (1/3)π(r^2 /4)k = (1/12)πr^2k

then the volume of the bottom portion is the

volume of the big cone minus the volume of the top cone

ie

V-v = (2/3)πr^2k – (1/12)πr^2k

= (2/3 – 1/12)π(r^2)k

= (7/12)π(r^2)k

is the volume of the bottom portion

so

ratio = (V-v) / v = 7/1

or 7:1

the bottom portion is 7 times the volume of the top portion

.

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