A few days ago
a very hard math question?
a right circular cone is divided into 2 portions, L and M, by a plane parallel to the base. The height of each portion is k units. Find the ratio of the volume of L to the volume of M.
Top 1 Answers
A few days ago
Favorite Answer
the volume of the cone is V = (1/3)πr^2h
where r = radius and h = height
since it is split in 2 parts with equal height k
the height of the big cone is h = 2k
so
V = (1/3)πr^2(2k) = (2/3)πr^2k is the volume of the big cone
now
the top portion is a cone with radius = r/2 and height = k
so
v = (1/3)π(r/2)^2k = (1/3)π(r^2 /4)k = (1/12)πr^2k
then the volume of the bottom portion is the
volume of the big cone minus the volume of the top cone
ie
V-v = (2/3)πr^2k – (1/12)πr^2k
= (2/3 – 1/12)π(r^2)k
= (7/12)π(r^2)k
is the volume of the bottom portion
so
ratio = (V-v) / v = 7/1
or 7:1
the bottom portion is 7 times the volume of the top portion
.
1
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