A few days ago
2x^2 – 4x + 1 = 0?
2x^2 – 4x + 1 = 0?
Top 6 Answers
A few days ago
Favorite Answer
I personally recommend using the Quadratic Equation to solve this, but I’ll do it another way.
First, you can factor out the 2.
2(x^2 – 2x) + 1 = 0
Next, divide both sides by 2.
x^2 – 2x + 1 = 0
Finally, factor this.
(x – 1)^2 = 0
The correct answer is x = 1.
0
A few days ago
2x^2 – 4x + 1 =
4x-4x+1=
=1
2 times x squared is 2 times itself, which is four
cancel out the negative and positive 4x and you get 1
0
A few days ago
you could do
2x^2 – 4x + 1 = 0
2x^2 – 4x = -1
2x(x – 2) = -1
which gives you the equations:
2x = -1
and
x – 2 = -1
so x is -1/2 and x is also 1
1
A few days ago
This is how I would solve it:
2x^2-4x+1=0
2x^2+1=4x
x^2+1=2x
x+1=sqrt of 2x
x=(sqrt. of 2x)-1
I hope this helps you. : )
0
A few days ago
+/- [sqrt(16-4(2)(1))]/2*2
= +/- sqrt(8)/4
= +/- sqrt(2)/2
0
A few days ago
i got -3.25
0
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