A few days ago
2-Ix+3I>1 inequalities involving absolute values?
how do i solve this problem. it is in the inequalities involving absolute values chapter.
Top 2 Answers
A few days ago
Favorite Answer
case 1 : x+3 >0, |x+3|=x+3
2-(x+3) > 1
2-x-3 > 1
-x-1 > 1
-x-1+1 > 1+1
-x > 2
x < 2 --- (1) case 2: x+3 < 0, |x+3|=-(x+3)=-x-3 2-(-x-3) > 1
2+x+3 >1
x+5 >1
x > -4 — (2)
case 3: x+3=0, x=-3 — (3)
-4 < x < 2 (x lies between -4 and 2)
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4 years ago
a million) I3x + 2I = – 8 |3x+2| is often advantageous and would by no skill = -8. No answer 2) I3x + 2I < - 8 |3x+2| is often advantageous and would by no skill < -8. No answer 3) I3x + 2I ? - 8 real for all x
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